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0=(4x^2)-66x+272
We move all terms to the left:
0-((4x^2)-66x+272)=0
We add all the numbers together, and all the variables
-(4x^2-66x+272)=0
We get rid of parentheses
-4x^2+66x-272=0
a = -4; b = 66; c = -272;
Δ = b2-4ac
Δ = 662-4·(-4)·(-272)
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(66)-2}{2*-4}=\frac{-68}{-8} =8+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(66)+2}{2*-4}=\frac{-64}{-8} =+8 $
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